# Ex.1.4 Q7 Integers Solution - NCERT Maths Class 7

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## Question

An elevator descends into a mine shaft at the rate of $$6 \text{ m/min}$$. If the descent starts from $$10\;\rm{m}$$ above the ground level, how long will it take to reach $$-350\;\rm{m}$$?

Video Solution
Integers
Ex 1.4 | Question 7

## Text Solution

Steps:

Total distance covered by an elevator

\begin{align}& =10-(-350)\text{m} \\ & =10+\left( 350 \right) \\ & =360\,\text{m} \end{align}

So, time taken to cover a distance of $$6 \rm{m}=1$$ min

Therefore, time taken to cover $$360 \text{ m}$$

\begin{align}&=\text{ 360 }\!\!\div\!\!\text{ 6 } \\ & =\text{ 60}\,\text{minutes} \end{align}

($$1$$ hour $$= 60$$ minutes)

Thus, the elevator will reach $$–350\;\rm{m}$$ from $$10\;\rm{m}$$ in $$1$$ hour.

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