# Ex 13.1 Q7 Exponents and Powers Solution- NCERT Maths Class 7

## Question

Simplify:

(i) $${{(-4)}^{3}}$$

(ii) $$(-3)\times {{(-2)}^{3}}$$

(iii) $${{(-3)}^{2}}\times {{(-5)}^{2}}$$

(iv)  $${{(-2)}^{3}}\times {{(-10)}^{3}}$$

Video Solution
Exponents And Powers
Ex 13.1 | Question 7

## Text Solution

What is unknown?

Base and Exponent

Reasoning:

In this question we will multiply the base and the number of times it’s exponent to simplify the given statement.

Steps:

(i) $${{(-4)}^{3}}$$

\begin{align} &\!=\!-4\times\! -4\!\times\! -4\!\\&=\!-\!64 \end{align}

(ii) $$(-3)\times {{(-2)}^{3}}$$

\begin{align}&=\!-3x\left( -2\!\times\!\!\!-2\times\!\!-2 \right)\\&=-3\!\times\!\!-8\\&=24\end{align}

(iii) $${{(-3)}^{2}}\times {{(-5)}^{2}}$$

\begin{align}&\!=\!-3x\!-\!3x(\!-5x\!-5)\\&=9\times 25\\&=225 \end{align}

(iv)  $${{(-2)}^{3}}\times {{(-10)}^{3}}$$

\begin{align}&\!=\!-\!\!2x\!-\!\!2x\!-\!\!2x(\!-\!\!10x\!-\!\!10x\!-\!\!10)\\&=-8x-1000\\&=8000 \end{align}

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