# Ex.14.2 Q7 Statistics Solution - NCERT Maths Class 9

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## Question

The value of \(π\) upto \(50\) decimal places is given below:

\(3.14159265358979323846264338327950288419716939937510\)

(i) Make a frequency distribution of the digits from \(0\) to \(9\) after the decimal point.

(ii) What are the most and the least frequently occurring digits?

## Text Solution

**What is known?**

- The value of ‘\(π\)’ upto \(50\) decimel places.

**What is unknown?**

- Constructing a required frequency distribution table
- And finding the most and the least frequently occurring digits.

**Reasoning:**

We can count each digit and can be written in front of them , like this we can draw frequency distribution table and can be concluded about most or least frequently occurring digits.

**Steps:**

We can represent the data by constructing a simple, ungrouped frequency distribution table as follows.

DIGITS |
TALLY MARKS |
FREQUENCY OF OCCURRENCE |

\(0 \) | || | 2 |

\(1 \) | 5 | |

\(2 \) | 5 | |

3 | 8 | |

4 | |||| | 4 |

5 | 5 | |

6 | |||| | 4 |

7 | |||| | 4 |

8 | 5 | |

9 | 8 | |

TOTAL |
50 |

If can be easily observed from the table that

- The most frequently occurring digits are \(3\) and \(9\) with a max frequency of \(8\) and
- The least frequently occurring digit is \(‘0’\) with a lowest frequency of \(2\).