# Ex 2.5 Q7 Fractions and Decimals Solution- NCERT Maths class 7

## Question

Dinesh went from place \(A\) to place \(B\) and from there to place \(C\). \(A\) is \(7.5\,\rm{km}\) from \(B\) and \(B\) is \(12.7\,\rm{km}\) from \(C\). Ayub went from place \(A\) to place \(D\) and from there to place \(C\). \(D\) is \(9.3\,\rm{km}\) from \(A\) and \(C\) is \(11.8\,\rm{km}\) from \(D\).Who travelled more and how much ?

## Text Solution

**What is known?**

Distance between points. Dinesh went from place \(A\) to \(B\) and then \(B\) to \(C\). Ayub went from place \(A\) to \(D\) then \(D\) to \(C\).

**What is unknown?**

Who travelled more and how much.

**Reasoning: **

Calculate by all the distance travelled by Dinesh to how much he travelled then calculate distance travel by Ayub.

**Steps:**

Given

Distance travelled by Dinesh from \(A\) to \(B = 7. 5\,\rm{km}\)

And from place \(B\) to place \( C = 12.7 \,\rm{km}\)

\(\therefore \) Total distance travelled by Dinesh

\[\begin{align} &= AB+ BC\\&= 7.5\,\rm{km} + 12.7\,\rm{km}\\&= 20.2 \,\rm{km}\end{align}\]

Distance travelled by Ayub from place \(A\) to place \(D = 9.3 \,\rm{km}\)

And from place \(D\) to place \(C = 11.8\,\rm{km}\)

\(\therefore \) Total distance travelled by Ayub

\[\begin{align}&= 9.3\,\rm{km} + 11.8 \,\rm{km}\\&= 21.1 \,\rm{km}\end{align}\]

On comparing the total distance travelled by Dinesh and Ayub, we get

\( 21.1\,\rm{km}\)\( >\) \( 20.2\,\rm{km}\)

Distance travelled by Ayub > Distance travelled by Dinesh

\(\therefore \) Ayub covered more distance by Dinesh is

\[\begin{align}&= 21.1 -20.2\\&= 0.9 \,\rm{km}\\&= 0.9 × 1000 \,\rm{m}\\&= 900\,\rm{m}\end{align}\]