# Ex.2.5 Q7 Linear Equations in One Variable Solution - NCERT Maths Class 8

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## Question

Simplify and solve the linear equation $$3(t - 3) = 5(2t + 1)$$

Video Solution
Linear Equations
Ex 2.5 | Question 7

## Text Solution

What is known?

Equation

What is unknown?

Value of the variable

Reasoning:

First open the brackets then transpose variable to one side and constant to another side.

Steps:

\begin{align}3\left( {t \! - \! 3} \right) & \! = \! 5\left( {2t \! + \! 1} \right) \\3t \! - \! 9 & \! = \! 10t \! + \! 5 \\\quad\quad\quad\text{(Opening }& \text{the brackets)}\\- 9 \! - \! 5 & \! = \! 10t \! - \! 3t \\ - 14 & \! = \! 7t \\t & \! = \! \frac{{ - 14}}{7} \\t & \! = \! - 2 \\\end{align}

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