Ex. 6.6 Q7 Triangles Solution - NCERT Maths Class 10

Go back to  'Ex.6.6'

Question

In Fig. below, two chords \(AB\) and \(CD\) intersect each other at the point \(P. \)

Prove that:

(i) \(\Delta APC\,\text{~}\Delta {\text{ }}DPB\)

(ii) \(AP. PB = CP. DP \)

Text Solution

Reasoning:

As we know that, two triangles, are similar if:

(i) Their corresponding angles are equal.

(ii) Their corresponding sides are in the same ratio.

As we know that angles in the same segment of a circle are equal.

Steps:

(i) In, \(\Delta APC \;\text{and}\; \Delta DPB\)

 

\(\angle APC = \angle DPB\)

(Vertically opposite angles)

\(\angle PAC = \angle PDB\)

(Angles in the same segment)

\(\Rightarrow \Delta APC\text{~}\Delta DPB\)

(A.A criterion)

(ii) In, \(\Delta APC \;\text{and}\; \Delta DPB\)

\[\begin{align} \frac{{AP}}{{PD}}& = \frac{{PC}}{{PB}} = \frac{{AC}}{{DB}}  \\ & \quad \left[ {\Delta APC\text{~}\Delta DPB} \right]\\ \frac{{AP}}{{PD}} &= \frac{{PC}}{{PB}} \end{align}\]

\(\Rightarrow \;\;AP.PB = PC.PD\)

  
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