Ex.7.2 Q7 Coordinate Geometry Solution - NCERT Maths Class 10


Find the coordinates of a point \(A\), where \(AB\) is the diameter of circle whose center is \((2, -3)\) and \(B\) is \((1, 4)\)

 Video Solution
Coordinate Geometry
Ex 7.2 | Question 7

Text Solution


The coordinates of the point \(P(x, y)\) which divides the line segment joining the points \(A(x_1, y_1)\) and \(B(x_2, y_2)\), internally, in the ratio \(m_1 : m_2\) is given by the Section Formula.

What is the known?

The \(x\) and \(y\) co-ordinates of the center of the circle and one end of the diameter \(B\).

What is the unknown?

The coordinates of a point \(A\).


From the Figure,


  • Let the coordinates of point \(A\) be \((x, y)\).
  • Mid-point of \(AB\) is \(C\) \((2, -3)\), which is the center of the circle.

\(\begin{align} \therefore \; (2, - 3) &= \left( {\frac{{x + 1}}{2},\frac{{y + 4}}{2}} \right)  \end{align}\)

\(\begin{align} \Rightarrow \frac{{x + 1}}{2}& = 2\;\;{\text{ and }}\;\;\frac{{y + 4}}{2} = - 3 & & \end{align}\) (By Cross multiplying & transposing)

\(\begin{align} \Rightarrow x + 1 &= 4\;\;{\text{ and }}\;\;y + 4 = - 6 \end{align}\)

\(\begin{align} \Rightarrow x &= 3\;\;{\text{ and }}\;\;y = - 10\end{align}\)

Therefore, the coordinates of \(A\) are \((3, -10)\)

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