# Ex.7.2 Q7 Coordinate Geometry Solution - NCERT Maths Class 10

## Question

Find the coordinates of a point \(A\), where \(AB\) is the diameter of circle whose center is \((2, -3)\) and \(B\) is \((1, 4)\)

## Text Solution

**Reasoning:**

The coordinates of the point \(P(x, y)\) which divides the line segment joining the points \(A(x_1, y_1)\) and \(B(x_2, y_2)\), internally, in the ratio \(m_1 : m_2\) is given by the Section Formula.

**What is the known?**

The \(x\) and \(y\) co-ordinates of the center of the circle and one end of the diameter \(B\).

**What is the unknown?**

The coordinates of a point \(A\).

**Steps:**

From the Figure,

Given,

- Let the coordinates of point \(A\) be \((x, y)\).
- Mid-point of \(AB\) is \(C\) \((2, -3)\), which is the center of the circle.

\(\begin{align} \therefore \; (2, - 3) &= \left( {\frac{{x + 1}}{2},\frac{{y + 4}}{2}} \right) \end{align}\)

\(\begin{align} \Rightarrow \frac{{x + 1}}{2}& = 2\;\;{\text{ and }}\;\;\frac{{y + 4}}{2} = - 3 & & \end{align}\) (By Cross multiplying & transposing)

\(\begin{align} \Rightarrow x + 1 &= 4\;\;{\text{ and }}\;\;y + 4 = - 6 \end{align}\)

\(\begin{align} \Rightarrow x &= 3\;\;{\text{ and }}\;\;y = - 10\end{align}\)

Therefore, the coordinates of \(A\) are \((3, -10)\)