# Ex.2.3 Q8 fractions-and-decimals Solutions-Ncert Maths Class 7

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## Question

a) i) Provide the number in the box $$□$$, such that \begin{align} \frac{2}{3}\times \square =\frac{10}{30}\end{align}

ii) The simplest form of the number obtained in $$□$$ is ―.

b) i) Provide the number in the box $$□$$, such that  \begin{align} \frac{3}{5}\times \,\square =\frac{24}{75}\end{align}

ii) The simplest form of the number obtained in □ is ―.

Video Solution
Fractions And Decimals
Ex 2.3 | Question 8

## Text Solution

Steps:

(a)

What is known?

Equations.

What is unknown?

Value of the box.

Reasoning:

To make L.H.S. $$=$$ R.H.S. we have to multiple numerator by $$5$$ and denominator by $$10$$.

i)\begin{align} \frac{2}{3}\times \square =\frac{10}{30}\end{align}

$=\frac{2}{3}\times \frac{5}{10}=\frac{10}{30}$

Therefore, the number in the box □, such that \begin{align} \frac{2}{3} \times \square = \frac{{10}}{{30}}{\text{ is }}\frac{5}{{10}}\end{align}

ii) The simplest form of the number obtained in \begin{align} \frac{5}{{10}}{\text{ is }}\frac{1}{2}\end{align} .

(b)

What is known?

Equations.

What is unknown?

Value of the box.

Reasoning:

To make L.H.S. $$=$$ R.H.S. we have to multiple numerator by $$8$$ and denominator by $$15$$.

i)  \begin{align} \frac{3}{5}\times \,\square =\frac{24}{75}\end{align}

\begin{align}=\frac{3}{5}\times \frac{8}{15}=\frac{24}{75} \\\end{align}

Therefore, the number in the box $$□$$, such that \begin{align} \frac{3}{5} × □ = \frac{{24}}{{75}} \rm \,is\, \frac{8}{{15}}\end{align}

ii) As \begin{align} \frac{8}{{15}}\end{align} can’t be simplified further. Therefore, its simplest form is \begin{align} \frac{8}{{15}}\end{align} .

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