# Ex.6.1 Q8 Squares and Square Roots Solutions - NCERT Maths Class 8

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## Question

(i)  Express $$49$$ as the sum of $$7$$ odd numbers.

(ii) Express $$121$$ as the sum of $$11$$ odd numbers.

Video Solution
Squares And Square Roots
Ex 6.1 | Question 8

## Text Solution

What is known?

Sum of $$7$$ odd number is $$49$$

Sum of $$11$$ odd number is $$121$$

What is uknown?

Express $$49$$ as the sum of $$7$$ odd numbers and $$121$$ as the sum of 11 odd numbers.

Reasoning:

The sum of successive odd natural numbers is $$n^2$$.

Steps:

(i) $$49 = {\left( 7 \right)^2}$$

Therefore ,$$49$$ is the sum of first $$7$$ odd natural numbers

$$49 = 1 + 3 + 5 + 7 + 9 + 11 + 13$$

(ii) $$121={\left(11 \right)^2}$$

Therefore ,$$121$$ is the sum of first $$11$$ odd natural numbers

$$121 = \left[ \begin{array}{l} 1 + 3 + 5 + 7 + 9 + 11 + \\13 + 15 + 17 + 19 + 21 \\ \end{array} \right]$$

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