# EX.2.1 Q9 Linear Equations in One Variable Solutions - NCERT Maths Class 8

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## Question

Solve the equation:

\({\rm{ 7}}x-{\rm{9}} = {\rm{16}}\)

Video Solution

Linear Equations

Ex 2.1 | Question 9

## Text Solution

**What is known?**

Equations

**What is unknown?**

Value of the variable

**Reasoning:**

In an equation values of left-hand side (LHS) and right-hand side (RHS) are equal. The two sides of the equation are balanced. We perform mathematical operations so that the balance is not disturbed.

**Steps:**

Transposing \((- 9)\) to RHS, we get

\[\begin{align}{\rm{7}}x &= {\rm{16 }} + {\rm{ 9 }}\\{\rm{7}}x &= {\rm{25}}\end{align}\]

Now dividing both sides by \(7\):

\[\begin{align}\frac{{7x}}{7}\,\, &= \,\,\frac{{25}}{7}\end{align}\]

We get \(\begin{align}x = 3.57\end{align}\)