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# Ex.6.1 Q9 Squares and Square Roots Solutions - NCERT Maths Class 8

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## Question

How many numbers lie between squares of the following numbers?

(i) $$12\; \text{ and} \; 13$$

(ii) $$25\; \text{and} \; 26$$

(iii) $$99\; \text{and} \; 100$$

Video Solution
Squares And Square Roots
Ex 6.1 | Question 9

## Text Solution

What is known?

Numbers

What is uknown?

How many number lie between squares of given number.

Reasoning:

There lies “$$2n$$” number between the square of the number $$n$$ and $$(n+1)$$

Steps:

(i) $$12\; \text{ and} \; 13$$

Here,$$n=12$$ gives $$2 \times 12 = 24$$, i.e., $$24$$ numbers between $${\left( {12} \right)^2}$$ and $${\left( {13} \right)^2}$$

(ii) $$25\; \text{and} \; 26$$

Here, $$n=25$$ gives $$2 \times 25 = 50$$, i.e., $$50$$ numbers. between $${\left( {25} \right)^2}$$ and $${\left( {26} \right)^2}$$

(iii) $$99\; \text{and} \; 100$$

Here, $$n=99$$ gives $$2 \times 99 = 198$$, i.e., $$198$$ numbers between $${\left( {99} \right)^2}$$ and $${\left( {100} \right)^2}$$

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