# Ex.6.4 Q9 Triangles Solution - NCERT Maths Class 10

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## Question

Sides of two similar triangles are in the ratio \(4 : 9.\) then the areas of these triangles are in the ratio

(A) \(2: 3\) (B) \(4 : 9\) (C) \(81 : 16\) (D) \(16 : 81\)

## Text Solution

**Reasoning:**

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

**Steps: **

We know that,

Ratio of the areas of two similar triangles= square of the ratio of their sides

\( = {(4\;:\;9)^2}\\= 16 : 81\)

The answer is (d) \(16 : 81\)