A rectangular lot is 275 feet deep, and it contains 2/3 of an acre. What is the length of the lot?

Solution:

From the question,

it is given that  rectangular lot is 275 feet deep, and it contains 2/3 of an acre.

We know that,

1 acre = 43,560 square feet

So, area of rectangular lot = (2/3) × 43,560

= 29,040 square feet.

Let us assume m is the length of the lot and n is the depth of the lot.

Then the area of the lot,

A = mn

We have A = 29,040 square feet,

n = 275 feet

29,040 = m × 275

By simplification we get,

m = 29,040/275

m = 105.6 feet

Therefore, the length of the lot is 105.6 feet.

---

A rectangular lot is 275 feet deep, and it contains 2/3 of an acre. What is the length of the lot?

Summary:

A rectangular lot is 275 feet deep, and it contains 2/3 of an acre. The length of the lot is 105.6 feet.