# A solid iron cuboidal block of dimensions 4.4 m × 2.6 m × 1 m is cast into a hollow cylindrical pipe of an internal radius of 30 cm and thickness of 5 cm. Find the length of the pipe?

Volumes are very important quantities that have many real-life applications. Starting from the gas cylinder in your homes to laboratory tests in hospitals, preciseness of volumes of substances is always kept in mind. Now let's solve a problem regarding volumes of cylinders and blocks.

## Answer: The height of the hollow cylindrical pipe with an internal radius of 30 cm and thickness of 5 cm cast from the given solid block is 112 m.

Let's understand the solution in detail.

**Explanation:**

From the above information, the things known about the hollow cylinder are:

Internal radius, r = 30 cm

Thickness, t = 5 cm

Let the length of the pipe be h.

Therefore, the external radius, R is given by the sum of the internal radius and the thickness.

Hence, R = r + t = 30 + 5 = 35 cm.

We know that the volume of cuboid = volume of hollow cylinder

Therefore, 440 × 260 ×100 = π (R^{2} – r^{2}) h

After converting all quantities in meters:

440 × 260 × 100 = 22/7 (35^{2} – 30^{2}) h

⇒ 440 × 260 × 100 = 22/7 (325) h

Hence, h = 11200 cm = 112 m

### Hence, the height of the hollow cylindrical pipe with an internal radius of 30 cm and thickness of 5 cm cast from the given solid block is 112 m.

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