# What is the HCF of 2, 4, and 8?

The largest possible number which divides the given numbers exactly without leaving any remainder is called the HCF (Highest Common Factor).

## Answer: HCF of 2, 4, and 8 is 2

HCF of 2, 4, and 8 is the highest number that divides 2, 4, and 8 exactly leaving the remainder 0.

## Explanation:

We will show two methods to find the highest common factor of 2, 4 and 8

We can find the HCF by the following methods

- HCF of 2, 4, and 8 by Listing the Common Factors
- HCF of 2, 4, and 2 by Prime Factorization

### Method 1: HCF of 2, 4 and 8 by Listing the Common Factors

The factors of 2, 4, and 8 are given below

Clearly, the common factors of 2, 4, and 8 are 1, 2, 3, 4, 6 and 2

The highest common factor of 2, 4, and 8 is 2.

### Method 2: HCF of 2, 4, and 8 by Prime Factorization

Let us represent 2, 4, and 4 as a product of its prime factors.

Prime factorization of 2 = 2

Prime factorization of 4 = 2 × 2

Prime factorization of 8 = 2 × 2 × 2

Observe that the common factor in the prime factorization of 2, 4, and 8 is 2.

So, HCF of 2, 4, and 8 is 2.

You can find the HCF in any of the above methods but the solution will be the same.