What is the HCF of 272 and 425?
HCF (Highest Common Factor) of two numbers is the greatest possible number which divides the two numbers exactly without any remainder.
Answer: HCF of 272 and 425 is 17
Let us see how to find the HCF of 272 and 425
Explanation:
HCF of 272 and 425 will the highest possible number that divides 272 and 425 exactly, that is, leaving the remainder 0
We will explain the HCF of 272 and 425 using the following two methods.

Prime factorization Method

Long division Method
Methods to Find HCF of 272 and 425
Method 1: HCF of 272 and 425 by Prime Factorization
Let us express 272 and 425 as a product of its prime factors
Prime factorization of 272 is 2 × 2 × 2 × 2 × 17
Prime factorization of 425 is 5 × 5 × 17
Common factor = 17
HCF is the product of the prime factors that are common to the prime factorization of 272 and 425
HCF of 272 and 425 is 17
Method 2: HCF of 272 and 425 by Long Division

Step 1: Divide the largest number 425 by the smaller number 272 and check the remainder.

Step 2: Make the remainder of the above step as the divisor and the divisor of the above step as the dividend and perform the long division again.

Step 3: Continue till you get remainder as 0 and HCF of 272 and 425 is the last divisor obtained.
You can find the HCF of 272 and 425 in any of the above methods but the solution will be the same.