# What is the HCF of 4, 8, and 12?

HCF (Highest Common Factor) of two numbers is the largest possible number which divides the two numbers exactly without leaving any remainder.

## Answer: HCF of 4, 8, and 12 is 4

HCF of 4, 8, and 12 is the highest number that divides 4, 8, and 12 exactly leaving the remainder 0.

## Explanation:

We will show two methods to find the highest common factor of 4, 8 and 12.

We can find the HCF by the following methods

- HCF of 4, 8, and 12 by Listing the Common Factors
- HCF of 4, 8, and 12 by Prime Factorization

### Method 1: HCF of 4, 8, and 12 by Listing the Common Factors

The factors of 4, 8, and 12 are given below

Here, the common factor among the factors of 4, 8, and 12 is 4.

So, the highest common factor of 4, 8, and 12 is 4.

### Method 2: HCF of 4, 8, and 12 by Prime Factorization

Let us represent 4, 8, and 12 as a product of its prime factors.

Prime factorization of 4 = 2 × 2

Prime factorization of 8 = 2 × 2 × 2

Prime factorization of 12 = 2 × 2 × 3

Observe that the common factors in the prime factorization of 4, 8, and 12 are 2 and 2.

So, HCF of 4, 8, and 12 is, 2 × 2 = 4

The solution of HCF of 4, 8, and 12 is the same as any of the above methods.