In this rectangular box, EF = 16, FD = 5, and DB = 30. Find AF.

Solution:

Given, DB = 30, FD = 5 and EF = 16

We have to find AF.

The given figure is a cuboid.

From the figure,

AB = EF = 16

In triangle ADB, using Pythagoras theorem,

DB² = AB² + AD²

(30)² = (16)² + AD²

900 = 256 + AD²

AD² = 900 - 256

AD² = 644

Taking square root,

AD = √644

AD = 2√161

Again, using Pythagoras theorem,

FA² = DF² + AD²

FA² = (5)² + (2√161)²

FA² = 25 + (4(161))

FA² = 25 + 644

FA² = 669

Taking square root,

FA = √669

FA = 25.87

Therefore, the value of AF is 25.87 units.

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In this rectangular box, EF = 16, FD = 5, and DB = 30. Find AF. 

Summary:

In this rectangular box, EF = 16, FD = 5, and DB = 30, then AF is 25.87 units.