# Solve 2x^{2} = 4x - 7 using the quadratic formula?

**Solution:**

Given that:

2x^{2} = 4x - 7

It can be written as in arranged form as :

2x^{2} - 4x + 7 = 0

The formula for the standard form of quadratic equation ax^{2} + bx + c = 0 is written as

x = [−b ± √(b^{2} − 4ac)] / 2a

From the given equation we know that

a = 2

b = -4

c = 7

Substituting it in the formula

x = [ -(-4) ± √{(-4)^{2} - 4(2)(7)} ] / 2(2)

x = [ 4 ± √{16 - 56} ] / 4

By further calculation

x = [ 4 ± √(-40) ] / 4

x = [ 4 ± 2√10 i ] / 4

x = (2 ± √10i)/2

Therefore, the values of x are (2 + √10 i)/2 and (2 - √10 i)/2.

# Solve 2x^{2} = 4x - 7 using the quadratic formula?

**Summary: **

By solving 2x^{2} = 4x - 7 using the quadratic formula, the values of x are (2 + √10 i)/2 and (2 - √10 i)/2.