Solve 3[-x + (2 x + 1)] = x - 1.

Solution:

Given equation is 3[-x + (2x + 1)] = x -1

Solving the equation by isolating the variables and by the method of transposing.

⇒ 3[-x + 2x + 1] = x - 1

⇒ 3[x + 1] = x - 1

⇒ 3x + 3 = x - 1

⇒ 2x = -4

⇒ x = -4/2

⇒ x = -2

Solve 3[-x + (2 x + 1)] = x - 1.

Summary:

Solving 3[-x + (2 x + 1)] = x - 1, we get x = -2