# What are the coordinates of the turning point for the function f(x) = (x + 2)^{3} - 4?

**Solution:**

The given function is f(x) = (x + 2)^{3} - 4

The turning point of a function where the f’(x) = 0

f’(x) = 3(x + 2)^{2}

To find the value of x, equate the first derivative equal to 0.

3(x + 2)^{2} = 0

x + 2 = 0

x = -2

At the turning point the x-coordinate is -2.

Substitute x = -2 in the given function

f(-2) = ((-2) + 2)^{3} - 4

f(-2) = -4

At the turning point the y-coordinate is -4.

Therefore, the turning point is (-2, -4).

## What are the coordinates of the turning point for the function f(x) = (x + 2)^{3} - 4?

**Summary:**

The coordinates of the turning point for the function f(x) = (x + 2)^{3} - 4 is (-2, -4).

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