# What is the discriminant of quadratic equation x^{2} + 11x + 121 = x + 96?

**Solution:**

Given: Quadratic equation is x^{2} + 11x + 121 = x + 96

We have to find the discriminant of x^{2} + 11x + 121 = x + 96

We know that the discriminant of ax^{2} + bx + c = 0 is given by b^{2} - 4ac.

⇒ x^{2} + 11x + 121 = x + 96

By transposing we get,

⇒ x^{2 }+ 11x - x + 121 - 96 = 0

⇒ x^{2} + 10 x + 25 = 0

Where, a = 1 , b = 10 and c = 25

The discriminant of ax^{2} + bx + c = 0 is b^{2} - 4ac

= 10^{2} - 4(1)(25)

= 100 - 100 = 0

Therefore, the discriminant of the quadratic equation is 0.

## What is the discriminant of quadratic equation x^{2} + 11x + 121 = x + 96?

**Summary:**

The discriminant of the quadratic equation x^{2} + 11x + 121 = x + 96 is 0.

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