What is the equation in point-slope form of the line that passes through the given point and has the given slope. M = 5/3. (4, -2)?

Solution:

Given, slope m = 5/3

The point is (4, -2)

We have to find the equation of the line in point-slope form.

The equation of the line in point-slope form is given by

\((y-y_{0})=m(x-x_{0})\)

So, (y - (-2)) = 5/3(x - 4)

(y + 2) = 5/3(x - 4)

3(y + 2) = 5(x - 4)

3y + 6 = 5x - 20

5x - 3y - 20 - 6 = 0

5x - 3y - 26 = 0

Therefore, the equation of the line is 5x - 3y - 26 = 0.

What is the equation in point-slope form of the line that passes through the given point and has the given slope. M = 5/3. (4, -2)?

Summary:

The equation in point-slope form of the line that passes through the given point and has the given slope. M = 5/3. (4, -2) is 5x - 3y - 26 = 0.