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Write the equation of the circle with center (-1, -3) and (-7, -5) a point on the circle.
Solution:
The standard form of the equation of a circle is given by
(x - a)2 + (y - b)2 = r2
Where, a and b are the coordinates of the centre
r is the radius
Given, centre = (-1, -3) and (x , y) = (-7, -5)
Substituting the values in standard form of equation we get,
(-7 - (-1))2 + (-5 - (-3))2 = r2
(-6)2 + (-2)2 = r2
r2 = 36 + 4
r = √40
Thus, the radius of the circle is √40 units.
The equation of a circle can be written as
(x - (-1))2 + (y - (-3))2 = (√40)2
(x + 1)2 + (y + 3)2 = 40
Therefore, the equation of a circle is (x + 1)2 + (y + 3)2 = 40.
Write the equation of the circle with center (-1, -3) and (-7, -5) a point on the circle.
Summary:
The equation of the circle with center (-1, -3) and (-7, -5) a point on the circle is (x + 1)2 + (y + 3)2 = 40.
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