What is the sum of the arithmetic sequence 6, 14, 22 …, if there are 26 terms?
Solution:
The arithmetic sequence formula is used for the calculation of the nth term of an arithmetic progression.
The arithmetic sequence is the sequence where the common difference remains constant between any two successive terms.
The sum of n terms when nth term is unknown can be found using the formula.
Sn = n/2[2a + (n − 1)d]
Given:
Arithmetic sequence 6, 14, 22 …26 terms.
⇒ a = 6
d = 14 - 6 = 8
⇒ n = 26
Now by substituting these values on the formula, we get
S26 = 26/2 [2(6) + (26−1)8]
By further calculation, we get
S26 = 13[12 + (25)8]
So we get,
S26 = 13[12 + 200]
S26 = 13[212]
S26 = 2756
Therefore, the sum of the arithmetic sequence is 2756.
What is the sum of the arithmetic sequence 6, 14, 22 …, if there are 26 terms?
Summary:
The sum of the arithmetic sequence 6, 14, 22 …, if there are 26 terms is 2756.
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