Where does the graph of y = sin x from x = 0 to x = 2π start?
At its minimum
At an x-intercept
At its maximum
Between an x-intercept and its maximum

Solution:

It is given that

y = sin x from x = 0 to x = 2π

We have to determine the starting point of the graph

The graph will start when x is 0

Substitute x = 0 in y = sin x

So we get

y = sin 0

y = 0

So the starting point is (0, 0).

The y value is 0 which is an x-intercept graph.

Therefore, the graph starts at an x-intercept.

Where does the graph of y = sin x from x = 0 to x = 2π start?
At its minimum
At an x-intercept
At its maximum
Between an x-intercept and its maximum

Summary:

The graph of y = sin x from x = 0 to x = 2π starts at an x-intercept.