from a handpicked tutor in LIVE 1-to-1 classes

# –1 is not a solution of the equation

(a) x + 1 = 0

(b) x – 1 = 2

(c) 2y + 3 = 1

(d) 2p + 7 = 5

**Solution:**

Let’s solve each of the equations

(a) x + 1 = 0

The given equation is x + 1 = 0

Thus,

x = –1

(b) x – 1 = 2

The given equation is x – 1 = 2

Thus,

x = 2 + 1

x = 3

(c) 2y + 3 =1

The given equation 2y + 3 = 1

Thus,

2y = 1 – 3

y = – 2/2

y = – 1

(d) 2p + 7 = 5

The given equation 2p + 7 = 5

Thus,

2p = 5 – 7

p = – 2/2

p = – 1

Hence the correct option is (b) x – 1 = 2

Thus, –1 is not a solution of the equation x – 1 = 2

**✦ Try This:** 2 is not a solution of the equation

(a) x – 2 = 0 (b) x – 2 = 2 (c) 2x – 3 = 1 (d) 2y + 1 = 5

Let’s solve each of the equations

(a) x – 2 = 0

The given equation is x – 2 = 0

Thus,

x = 2

(b) x – 2 = 2

The given equation is x – 2 = 2

Thus,

x = 2 + 2

x = 4

(c) 2x – 3 = 1

The given equation 2x – 3 = 1

Thus,

2x = 1 + 3

x = 4/2

x = 2

(d) 2y + 1 = 5

The given equation 2y + 1 = 5

Thus,

2y = 5 – 1

y = 4/2

y = 2

Hence the correct option is (b) x – 2 = 2

Thus, 2 is not a solution of the equation x – 2 = 2

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 4

**NCERT Exemplar Class 7 Maths Chapter 4 Solved Ex 2**

## –1 is not a solution of the equation (a) x + 1 = 0 (b) x – 1 = 2 (c) 2y + 3 = 1 (d) 2p + 7 = 5

**Summary:**

Thus, –1 is not a solution of the equation x – 1 = 2

**☛ Related Questions:**

visual curriculum