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# 500 persons are taking a dip into a cuboidal pond which is 80 m long and 50 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0.04m³

**Solution:**

Given, a cuboidal pond has dimensions 80 m long and 50 m broad.

500 persons are taking a dip into the pond.

Average displacement of water by a person is 0.04 m³.

We have to find the rise of water level in the pond.

Average displacement by 500 persons = 500(0.04)

= 20 m³

Volume of water raised in the pond = 20 m³

Volume of water rise in the cuboidal pond = length × width × depth

= 80 × 50 × h

= 4000 h

Now, the volume of water rise in the pond = average displacement of water by 500 persons.

4000 h = 20

h = 20/4000

h = 2/400

h = 1/200

h = 0.005 m

1 m = 100 cm

h = 0.005(100)

h = 0.5 cm

Therefore, the rise of water level in the pond is 0.5 cm

**✦ Try This: **800 persons are taking a dip into a cuboidal pond which is 100 m long and 80 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0.06m³ ?

**☛ Also Check: **NCERT Solutions for Class 10 Maths Chapter 13

**NCERT Exemplar Class 10 Maths Exercise 12.4 Problem 10**

## 500 persons are taking a dip into a cuboidal pond which is 80 m long and 50 m broad. What is the rise of water level in the pond, if the average displacement of the water by a person is 0.04m³

**Summary:**

500 persons are taking a dip into a cuboidal pond which is 80 m long and 50 m broad. The rise of water level in the pond, if the average displacement of the water by a person is 0.04m³ is 0.5 cm

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