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# Determine the point on the graph of the equation 2x + 5y = 20 whose x-coordinate is 5/2 times its ordinate

**Solution:**

Given, the equation is 2x + 5y = 20

The __x-coordinate__ is 5/2 times its ordinate i.e.,y-coordinate

We have to determine the point.

Given, x = (5/2)y

2x = 5y

Put 2x = 5y in the equation,

5y + 5y = 20

10y = 20

y = 20/10

y = 2

Put y = 2 in the equation,

2x + 5(2) = 20

2x + 10 = 20

2x = 20 - 10

2x = 10

x = 10/2

x = 5

Therefore, the point is (5, 2).

**✦ Try This: **Determine the point on the graph of the equation 2x + 3y = 12 whose x-coordinate is 3/2 times its ordinate.

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 4

**NCERT Exemplar Class 9 Maths Exercise 4.3 Sample Problem 3**

## Determine the point on the graph of the equation 2x + 5y = 20 whose x-coordinate is 5/2 times its ordinate

**Summary:**

In a two dimensional coordinate system (x, y), the x-coordinate is called abscissa and the y-coordinate is called the ordinate. The point on the graph of the equation 2x + 5y = 20 whose x-coordinate is 5/2 times its ordinate is (5, 2)

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