# Distance between two stations A and B is 690 km. Two cars start simultaneously from A and B towards each other, and the distance between them after 6 hours is 30 km. If the speed of one car is less than the other by 10 km/hr, find the speed of each car.

**Solution:**

Given, the distance between two stations A and B is 690 km.

Two cars start simultaneously from A and B towards each other.

The distance between the two cars after 6 hours is 30 km.

The speed of one car is less than the other by 10 km/hr.

We have to find the speed of each car.

Let the speed of the faster car be x km/hr.

The __speed__ of other car = (x - 10) km/hr

Let the first car start from point A and the other from point B

Let M and N be the position of the cars after 6 hours.

We know, distance = speed × time

Distance AM = x × 6 = 6x km

Distance BN = (x-10) × 6 = 6x - 60 km

According to the question,

6x + 6x - 60 + 30 = 690

12x = 690 + 30

12x = 720

x = 720/12

x = 60 km/hr

Now, (x - 10) = 60 - 10 = 50 km/hr

Therefore, the speed of the cars are 60 km/hr and 50 km/hr.

**✦ Try This: **Distance between two stations A and B is 720 km. Two cars start simultaneously from A and B towards each other, and the distance between them after 7 hours is 21 km. If the speed of one car is less than the other by 8 km/hr, find the speed of each car.

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 2

**NCERT Exemplar Class 8 Maths Chapter 4 Sample Problem 10**

## Distance between two stations A and B is 690 km. Two cars start simultaneously from A and B towards each other, and the distance between them after 6 hours is 30 km. If the speed of one car is less than the other by 10 km/hr, find the speed of each car

**Summary:**

Distance between two stations A and B is 690 km. Two cars start simultaneously from A and B towards each other, and the distance between them after 6 hours is 30 km. If the speed of one car is less than the other by 10 km/hr, the speed of each car is 60 km/hr and 50 km/hr.

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