Find the mean deviation about the mean for the data
Income per day (₹) Number of Persons
0-100 4
100-200 8
200-300 9
300-400 10
400-500 7
500-600 5
600-700 4
700-800 3
Solution:
The following table is formed.
Income per day | Number of person fi | Mid-point xi | fi xi | xi - x | fi xi - x |
0 -100 | 4 | 50 | 200 | 308 | 1232 |
100 - 200 | 8 | 150 | 1200 | 208 | 1664 |
200 - 300 | 9 | 250 | 2250 | 108 | 972 |
300 - 400 | 10 | 350 | 3500 | 8 | 80 |
400 - 500 | 7 | 450 | 3150 | 92 | 644 |
500 - 600 | 5 | 550 | 2750 | 192 | 960 |
600 - 700 | 4 | 650 | 2600 | 292 | 1168 |
700 - 800 | 3 | 750 | 2250 | 392 | 1176 |
Total | 50 | 17900 | 7896 |
Here,
N = 8∑i = 1 fi = 50 and 8∑i = 1 fi|xi - M| = 17900
Therefore,
x = 1/N 8∑i = 1 fixi
= 1/50 × 17900
= 358
Hence, the mean deviation about the median
M.D. (x)
= 8∑i = 1 |xi - x|
= 1/50 × 7896
= 157.92
NCERT Solutions Class 11 Maths Chapter 15 Exercise 15.1 Question 9
Find the mean deviation about the mean for the data: Income per day (₹) Number of Persons 0-100 4 100-200 8 200-300 9 300-400 10 400-500 7 500-600 5 600-700 4 700-800 3
Summary:
The mean deviation about the mean for the given data is 157.92
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