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# How many 3-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?

**Solution:**

For the number to be even the last digit must be 2, 4, or 6.

No. of ways of choosing first digit = 6

No. of ways of choosing second digit = 6

No. of ways of choosing the third digit = 3

By fundamental counting principle,

Therefore, total possible number of ways =6×6×3=108

NCERT Solutions Class 11 Maths Chapter 7 Exercise 7.1 Question 2

## How many 3-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?

**Summary:**

The total number of 3 digit numbers, that can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated is 108

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