# In a park of dimensions 20 m × 15 m, there is a L shaped 1m wide flower bed as shown in Fig. 9.61. Find the total cost of manuring for the flower bed at the rate of Rs 45 per m².

**Solution:**

Given, a park consists of a L shaped 1 m wide flower bed.

The dimensions of the park is 20 m × 15 m.

The cost of manuring for the flower bed is Rs 45 per m².

We have to find the total cost of manuring for the flower bed.

Area of flower bed = area of park ABCD - area of EFGD

The park is in the shape of a rectangle

__Area of rectangle__ = length × breadth

Considering the park ABCD,

Length = 15 m

Breadth = 20 m

Area = 15(20)

= 300 m²

Considering rectangle EFGD,

Length = 15 m - 1 m = 14 m

Breadth = 20 - 1 = 19 m

__Area__ = 14(19)

= 266 m²

Area of flower bed = 300 - 266

= 34 m²

Cost of manuring 1 m² = Rs. 45

Cost of manuring 34 m² = 45 × 34

= 1530

Therefore, the total cost of manuring is Rs. 1530/-

**✦ Try This: **If the circumference of a circle is reduced by 50%, then by how much percent is the area of the circle reduced?

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 11

**NCERT Exemplar Class 7 Maths Chapter 9 Problem 116**

## In a park of dimensions 20 m × 15 m, there is a L shaped 1m wide flower bed as shown in Fig. 9.61. Find the total cost of manuring for the flower bed at the rate of Rs 45 per m².

**Summary:**

In a park of dimensions 20 m × 15 m, there is a L shaped 1m wide flower bed as shown in Fig. 9.61. The total cost of manuring for the flower bed at the rate of Rs 45 per m² is Rs. 1530/-.

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