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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
In Fig. 10.8, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to :
a. 30º
b. 45º
c. 60º
d. 120º
Solution:
In triangle AOB
∠OBA = ∠BAO (angles opposite to equal sides are equal)
It is given that
∠BAO = 60º
So ∠OBA = 60º
As the angles in the same segment AC are equal
∠ABC = ∠ADC
We get
∠ADC = 60º
Therefore, ∠ADC is equal to 60º.
✦ Try This: BC is a diameter of the circle and ∠BAO = 50º. Then ∠ADC is equal to
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 10
NCERT Exemplar Class 9 Maths Exercise 10.1 Problem 9
In Fig. 10.8, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to : a. 30º, b. 45º, c. 60º, d. 120º
Summary:
In Fig. 10.8, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to 60º
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