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# In Fig. 10.8, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to :

a. 30º

b. 45º

c. 60º

d. 120º

**Solution:**

In triangle AOB

∠OBA = ∠BAO (angles opposite to equal sides are equal)

It is given that

∠BAO = 60º

So ∠OBA = 60º

As the angles in the same segment AC are equal

∠ABC = ∠ADC

We get

∠ADC = 60º

Therefore, ∠ADC is equal to 60º.

**✦ Try This:** BC is a diameter of the circle and ∠BAO = 50º. Then ∠ADC is equal to

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 10

**NCERT Exemplar Class 9 Maths Exercise 10.1 Problem 9**

## In Fig. 10.8, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to : a. 30º, b. 45º, c. 60º, d. 120º

**Summary:**

In Fig. 10.8, BC is a diameter of the circle and ∠BAO = 60º. Then ∠ADC is equal to 60º

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