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# Meenakshee cycles to her school at an average speed of 12 km/h and takes 20 minutes to reach her school. If she wants to reach her school in 12 minutes, her average speed should be

(a) 20/3 Km/h

(b) 16Km/h

(c) 20km/h

(d) 15 km/h

**Solution:**

Average speed of Meenakshi as she cycles to her school = 12km/h

Time taken to reach the school at the above speed = 20 minutes = 20/60 hours = 1/3 hours

Distance covered in 20 minutes = (1/3) × 12 = 4 km

If Meenakshi wants to reach in 12 minutes(12/60 = 1/5 hours) then her speed should be

Desired Speed = Distance to school/Time = 4/(1/5) = 20 km/h

To cover the same distance in 12 minutes the average speed should be 20 km/h

**✦ Try This: **Meenakshee cycles to her school at an average speed of 15 km/h and takes 25 minutes to reach her school. If she wants to reach her school in 15 minutes, her average speed should be (a) 25 Km/h, (b) 16Km/h, (c) 20km/h, (d) 15 km/h

Average speed of Meenakshi as she cycles to her school = 15km/h

Time taken to reach the school at the above speed = 25 minutes = 25/60 hours = 5/12 hours

Distance covered in 15 minutes = (5/12) × 15 = 25/4 km

If Meenakshi wants to reach in 15 minutes(15/60 = 1/4 hours) then her speed should be

Desired Speed = Distance to school/Time = (25/4)/(1/4) = 25 km/h

To cover the same distance in 15 minutes the average speed should be 25 km/h

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 13

**NCERT Exemplar Class 8 Maths Chapter 10 Problem 11**

## Meenakshee cycles to her school at an average speed of 12 km/h and takes 20 minutes to reach her school. If she wants to reach her school in 12 minutes, her average speed should be (a) 20/3 Km/h, (b) 16Km/h, (c) 20km/h, (d) 15 km/h

**Summary:**

Meenakshee cycles to her school at an average speed of 12 km/h and takes 20 minutes to reach her school. If she wants to reach her school in 12 minutes, then her average speed should be 20 km/h

**☛ Related Questions:**

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- If two quantities x and y vary directly with each other, then (a) x/y remains constant, (b) x - y re . . . .
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