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# My younger sister's age today is 3 times, what it will be 3 years from now minus 3 times what her age was 3 years ago. Find her present age

**Solution:**

Let the present age of her be x years

Then after 3 years, her age be (x + 3) years and 3 years ago her age would be (x - 3) years

The linear equation formed is:

x = 3 [(x + 3) - (x - 3)]

x = 3 [x + 3 - x + 3]

x = 3 [6]

x = 18

Thus, her present age is 18 years.

**✦ Try This:** My brother's age today is 2 times, what it will be 2 years from now minus 2 times what her age was 2 years ago. Find his present age.

Let his present age be x years

Then after 2 years, his age be (x + 2) years and 2 years ago his age would be (x - 2) years

A/Q

x = 2 [(x + 2) - (x - 2)]

x = 2 [x + 2 - x + 2]

x = 2 [4]

x = 8

Thus, his present age is 8 years.

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 4

**NCERT Exemplar Class 7 Maths Chapter 4 Problem 79**

## My younger sister's age today is 3 times, what it will be 3 years from now minus 3 times what her age was 3 years ago. Find her present age

**Summary:**

If my younger sister's age today is 3 times the age after 3 years minus 3 times her age 3 years ago, then her present age is 18 years

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