The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is
(a)11b + 30
(b) 10b + 30
(c) 11b + 3
(d) 10b + 3

Solution:

Given, the digit in the tens place of a two digit number is 3 more than the digit in the units place.

The digit at units place be b.

We have to find the number.

According to the question,

Unit’s digit = b

Ten’s digit = 3 + b

Number = tens digit + unit’s digit

= 10(3 + b) + b

= 10(3) + 10(b) + b

= 30 + 10b + b

= 30 + 11b

Therefore, the number is 11b + 30.

✦ Try This: The digit in the tens place of a two digit number is 4 less than the digit in the units place. Let the digit at units place be b. Then the number is

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 2

NCERT Exemplar Class 8 Maths Chapter 4 Problem 13

The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is (a)11b + 30, (b) 10b + 30, (c) 11b + 3, (d) 10b + 3

Summary:

The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is 11b + 30.

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