A circle is centered at (3, 8) and is tangent to the x-axis. Write its equation in standard form.

Solution:

The standard equation of the circle is (x - h)2 + (y - k)2 = r2

Where (h, k) is the center and r is the radius

From the center of the circle given (3, 8)

r = 8

The center moved 3 to the right

So we get (x - 3)

The center moved 8 to the up

So we get (y - 8)

(x - 3)2 + (y - 8)2 = 82

Therefore, the standard form of the equation is (x - 3)2 + (y - 8)2 = 82.

A circle is centered at (3, 8) and is tangent to the x-axis. Write its equation in standard form.

Summary:

A circle is centered at (3, 8) and is tangent to the x-axis. Its equation in standard form is (x - 3)2 + (y - 8)2 = 82.

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