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# Choose the equation below whose axis of symmetry is x = 2.

y = x^{2} + 4x + 2

y = x^{2} - 4

y = x^{2} - 2

y = x^{2} - 4x + 2

**Solution:**

Given axis of symmetry x = 2

The axis of symmetry is the vertical line that goes through the vertex of a parabola so the left side and the right side of it are symmetrical.

The axis of symmetry for ax^{2} + bx + c is given as x = -b/2a

Equate x = 2 with x = -b/2a

⇒ -b/2a = 2

Now, check the options, which satisfy this condition.

We get x^{2} - 4x + 2 as the required equation [since -(-4)/2 = 2]

## Choose the equation below whose axis of symmetry is x = 2.

**Summary:**

The equation is x^{2} - 4x + 2 whose axis of symmetry is x = 2.

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