Consider the quadratic function f(y) = 8y² - 7y + 6. What is the constant of the function?

Solution:

A quadratic function is of the form f(x) = ax² + bx + c, where a, b, and c are the numbers which are not equal to zero.

x = [-b ± √(b² - 4ac)]/2a

It is given that

f(y) = 8y² - 7y + 6

Here a = 8, b = -7 and c = 6

Where constant of the function c = 6.

Therefore, the constant of the function is 6.

Consider the quadratic function f(y) = 8y² - 7y + 6. What is the constant of the function?

Summary:

Consider the quadratic function f(y) = 8y² - 7y + 6. The constant of the function is 6.