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# Determine the standard form of the equation of the line that passes through (-7, 8) and (0, 2).

**Solution:**

The standard equation of a line is Ax + By + C = 0.

Equation of the line in the two point form is (y - y_{1}) = [(y_{2} - y_{1}) / (x_{2} - x_{1})] (x - x_{1}) ------(1)

Given that line passes through (-7, 8) and (0, 2)

∴ Substituting (x_{1}, y_{1}) = (-7, 8) and (x_{2}, y_{2}) = (0, 2) in equation (1),

(y - y_{1}) = [(y_{2 }- y_{1}) / (x_{2} - x_{1})] (x - x_{1})

(y - 8) = [(2 - 8) / (0 - (-7)] [x - (-7)]

(y - 8) = (-6/ 7) (x + 7)

7y - 56 = -6x - 42

6x + 7y - 14 = 0

This is the required equation of the line which is in the general form.

## Determine the standard form of the equation of the line that passes through (-7, 8) and (0, 2).

**Summary:**

The standard form of the equation of the line that passes through (-7, 8) and (0, 2) is 6x + 7y - 14 = 0.

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