# Factorise 2x^{2 }+ 7x + 3

To factors of the above equation will be in the form of (x + a) (x - b).

## Answer: The factors of 2x^{2 }+ 7x + 3 are ( x + 3) and (2x + 1)

Here's is the method.

**Explanation: **

To find the factors of 2x^{2 }+ 7x + 3 we need to split the middle term, that is, 7x.

7x = 6x + x

Therefore, 2x^{2 }+ 7x+ 3 can be written as 2x^{2 }+ 6x + x + 3 .

On taking '2x' common from first two terms and +1 from next two terms we get

2x (x + 3) +1 (x + 3)

(x + 3) (2x + 1)

## Thus, the factors of 2x^{2 }+ 7x + 3 are (x+3) and (2x+1)

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