Find the dimensions of a rectangle with a perimeter 100m whose area is as large as possible.
Solution:
It is given that
Perimeter of the rectangle = 100m
Area is as large as possible if both the values are the same number.
In order to have a maximum area of rectangle , the dimensions should be equal.
Consider the dimensions as x
So perimeter can be written as
2 (x + x) = 100
2 (2x) = 100
By further calculation
4x = 100
Divide both sides by 4
x = 25
Therefore, the dimensions of a rectangle is 25m × 25m.
Find the dimensions of a rectangle with a perimeter 100m whose area is as large as possible.
Summary:
The dimensions of a rectangle with a perimeter 100m whose area is as large as possible is 25m × 25m.
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