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# Find the next three terms of the sequence 3, 9, 27, 81, . . .

**Solution:**

Given,

The sequence 3, 9, 27, 81, . . .

This is a geometric sequence since there is a common ratio between each of them.

In this case, multiplying the previous term in the sequence by 3 gives the next term.

A_{n} = a_{1} r^{n - 1}.

Where, r = 3, a_{1} = 3.

Form of geometric sequence = a_{1} r^{n - 1}.

Substituting , we get,

a_{5} = 3(3)^{5 - 1}

= 3(3)^{4}

= 3(81)

= 243

a_{6} = 3 (3)^{6 - 1}

= 3(3)^{5}

= 3(243)

= 729

a_{7} = 3 (3)^{7 - 1}

= 3(3)^{6}

= 3(729)

= 2187

Therefore, the next three terms are 243, 729 and 2187.

## Find the next three terms of the sequence 3, 9, 27, 81, . . .

**Summary:**

The next three terms of the sequence 3, 9, 27, 81, . . . are243, 729 and 2187.

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