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# Find the value or values of y in the quadratic equation y^{2} + 4y + 4 = 7.

**Solution:**

It is given that,

y^{2} + 4y + 4 = 7

We know that,

(a + b)^{2} = a^{2} + 2ab + b^{2}

So, (y + 2)^{2} = 7

By transposing we get,

(y + 2)^{2} - 7 = 0

Then separating using the formula a^{2}-b^{2}^{ }= (a+b) (a-b), we get

(y + 2 -√7)(y + 2 + √7) = 0 By simplification we get, y = -2 + √7 or y = -2-√7

Therefore, the value or values of y is y = -2 + √7 or y = -2-√7.

## Find the value or values of y in the quadratic equation y^{2} + 4y + 4 = 7.

**Summary:**

The value or values of y in the quadratic equation y^{2} + 4y + 4 = 7 is y = -2 + √7 or y = -2-√7.

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