Find the value or values of y in the quadratic equation y² + 4y + 4 = 7.

Solution:

It is given that,

y² + 4y + 4 = 7

We know that,

(a + b)² = a² + 2ab + b²

So, (y + 2)² = 7

By transposing we get,

(y + 2)² - 7 = 0

Then separating using the formula a²-b² = (a+b) (a-b), we get

(y + 2 -√7)(y + 2 + √7) = 0 By simplification we get, y = -2 + √7 or y = -2-√7

Therefore, the value or values of y is y = -2 + √7 or y = -2-√7.

Find the value or values of y in the quadratic equation y² + 4y + 4 = 7.

Summary:

The value or values of y in the quadratic equation y² + 4y + 4 = 7 is y = -2 + √7 or y = -2-√7.