Learn Math Questions

from a handpicked tutor in LIVE 1-to-1 classes

from a handpicked tutor in LIVE 1-to-1 classes

# If P(A) = 0.50, P(B) = 0.40, then, and P(A ∪ B) = 0.88, then P(B|A) =

**Solution:**

Given: P(A) = 0.50, P(B) = 0.40 and P(A ∪ B) = 0.88

We know that the conditional probability is P(B|A) = P(A ⋂ B) / P(A)

We have P(A ∪ B) = P(A) + P(B) - P(A ⋂ B)

⇒ P(A ⋂ B) = P(A) + P(B) - P(A ∪ B)

⇒ P(A ⋂ B) = 0.50 + 0.40 - 0.88

⇒ P(A ⋂ B) = 0.90 - 0.88

⇒ P(A ⋂ B) = 0.02

Now, P(B|A) = P(A ⋂ B) / P(A) = 0.02 / 0.50 = 0.04

P(B|A) = 0.04

Therefore, the value of P(B|A) is 0.04

## If P(A) = 0.50, P(B) = 0.40, then, and P(A ∪ B) = 0.88, then P(B|A) =

**Summary:**

If P(A) = 0.50, P(B) = 0.40, then, and P(A ∪ B) = 0.88, then P(B|A) is 0.04

Math worksheets and

visual curriculum

visual curriculum