# If the Equation of a Circle is (x + 4)^{2} + (y - 6)^{2} = 25, its Center Point is?

**Solution:**

We will be using the equation of a circle with a center point (h, k) to solve this.

Let us solve it step by step.

The equation of circle, with a center point (h, k) and radius (r) is (x − h)^{2} + (y − k)^{2} = r^{2} .

Given that, (x + 4)^{2} + (y - 6)^{2} = 5^{2}

If you compare the both equations.

Center Point = (h, k) = (-4, 6) and radius (r) = 5

Thus, If the Equation of a Circle is (x + 4)^{2} + (y - 6)^{2} = 25, its Center Point is (-4, 6).

## If the Equation of a Circle is (x + 4)^{2} + (y - 6)^{2} = 25, its Center Point is?

**Summary:**

If the Equation of a Circle is (x + 4)^{2} + (y - 6)^{2} = 25, its Center Point is (-4, 6).

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