# If the equation of a line is y = 3x + 2, which point cannot be on the line? Is it (1/3, 3), (2, 8), (0, 2) or (7, 19)?

Equations can be represented in the cartesian plane by various curves. For example, linear equations are represented by straight lines. We will solve a problem that will clarify the concepts of straight lines.

## Answer: If the equation of a line is y = 3x + 2, then (7, 19) can't be on the line.

Let's understand the solution in detail.

**Explanation:**

Given equation of the line: y = 3x + 2.

Now, we substitute the value of the coordinates given to check if they lie on the line or not.

Substituting (1/3, 3), we get (3) = 3(1/3) + 2. This expression holds true. Hence, the point lies on the line.

Substituting (2, 8), we get (8) = 3(2) + 2. This expression holds true. Hence, the point lies on the line.

Substituting (0, 2), we get (2) = 3(0) + 2. This expression holds true. Hence, the point lies on the line.

Substituting (7, 21), we get (21) ≠ 3(7) + 2, as 21 ≠ 23. Hence, this expression is not true. Hence, the point (7, 21) does not lie on the line.