# Is there a number that is exactly 3 more than its cube?

**Solution:**

Given a number 3 times more than its cube times

Let the number be x

x = x^{3} + 3

x^{3} - x + 3 = 0

By solving this cubic equation, we get x ~ -1.6717

Therefore, the number -1.67 is 3 more than its cube

## Is there a number that is exactly 3 more than its cube?

**Summary:**

There is a number that is exactly 3 more than its cube, that is -1.67

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