# Solve x^{2} - 10x + 25 = 35 for x.

**Solution:**

Given x^{2} - 10x + 25 = 35

x^{2} - 10x + 25 - 35 = 0

x^{2} - 10x -10 = 0

Here we use quadratic formula for finding __roots__ of the equation

x = {-b ± √b² - 4ac}/2a

Here a = 1; b = -10; c = -10

x = {-(-10) ± √(-10)² - 4(-10)}/2(1)

x = (10 ± √100 + 40) /2

x = (10 ± √140) /2

x = 10 ± 11.8 /2

x = 10.9, -0.9

The solutions are 10.9, -0.9

## Solve x^{2} - 10x + 25 = 35 for x.

**Summary:**

By solving x^{2} - 10x + 25 = 35 for x, we get solutions as 10.9, -0.9

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